Quadratic Equation - Algebra -Single Correct Type Questions(JEE ADVANCED) Part 1

 Q.1

Correct Answer is:C
Solution Explain:










Q.2

Correct Answer is:C
Solution Explain:











Q.3

Correct Answer is:D
Solution Explain:









Q.4

Correct Answer is:C
Solution Explain:







Q.5

Correct Answer is:A
Solution Explain:








Q.6

Correct Answer is:C
Solution Explain:








Q.7

Correct Answer is:A
Solution Explain:












Q.8

Correct Answer is:C
Solution Explain:










Q.9

Correct Answer is:C
Solution Explain:









Q.10

Correct Answer is:B
Solution Explain:








Q.11

Correct Answer is:A
Solution Explain:









Q.12

Correct Answer is:B
Solution Explain:










Q.13

Correct Answer is:C
Solution Explain:










Q.14

Correct Answer is:A
Solution Explain:









Q.15

Correct Answer is:B
Solution Explain:










Q.16

Correct Answer is:B
Solution Explain:









Q.17

Correct Answer is:C
Solution Explain:








Q.18

Correct Answer is:B
Solution Explain:










Q.19

Correct Answer is:B
Solution Explain:









Q.20

Correct Answer is:D
Solution Explain:










Q.21

Correct Answer is:A
Solution Explain:









Q.22

Correct Answer is:B
Solution Explain:










Q.23

Correct Answer is:B
Solution Explain:










Q.24

Correct Answer is:B
Solution Explain:










Q.25

Correct Answer is:C
Solution Explain:









Q.26

Correct Answer is:A
Solution Explain:








Q.27

Correct Answer is:C
Solution Explain:









Q.28

Correct Answer is:A
Solution Explain:










Q.29

Correct Answer is:B
Solution Explain:










Q.30

Correct Answer is:C
Solution Explain:









Q.31

Correct Answer is:C
Solution Explain:









Q.32

Correct Answer is:C
Solution Explain:









Q.33

Correct Answer is:C
Solution Explain:










Q.34

Correct Answer is:D
Solution Explain:










Q.35

Correct Answer is:B
Solution Explain:











Q.36

Correct Answer is:D
Solution Explain:

Since, p(x) = 0 is a quadratic equation with real coefficients having purely imaginary roots
Therefore p(x) = ax2 + b where a and b are of same sign
Now p(p(x)) = 0 ⇒ a(ax2 + b)2 + b = 0
But if x is purely real or purely imaginary then x2 is purely real
So, (ax2 + b)2 is purely real and greater than or equal to zero 
⇒ p(p(x)) = a(ax2 + b)2 + b can never be zero
[as a and b are of same sign and b ≠ 0]
⇒ p(p(x)) = 0 can have only complex roots









Q.37

Correct Answer is:C
Solution Explain:









Q.38

Correct Answer is:B
Solution Explain:









Q.39

Correct Answer is:D
Solution Explain:









Q.40

Correct Answer is:A
Solution Explain:



Post a Comment (0)
Previous Post Next Post