Q.1
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Q.2
Solution Explain:
Let the 4 persons were A, B, C, D. First, we choose which two were shot = 4C2. Let C, D were shot.
Then C
D and A → C or D and B → C or D. Any person shooting any other person has probability = 1/3.
So, probability that C, D were shot
Hence ,probability that exactly 2 person were shot
Q.3
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Q.4
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Q.5
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Q.6
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Q.7
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Q.8
Solution Explain:
Suppose you flip a coin 10 times. Each toss has a 1/2 chance to be a tail.
P (getting 10 tails) = (1/2)×(1/2).......(1/2) (10 times) = (1/2)10
P (not getting 10 tails) = 1 - P (getting 10 tails) = 1 - (1/2)10
Suppose n people flip a coin 10 times,
P (n people not getting 10 tails) = (1- (1/2)10)n
P (someone in n get 10 tails) = 1 - (1- (1/2)10)n
P (someone in n get 10 tails) = 1 - (1- (1/2)10)n = 0.999
1 - 0.999 = (1- (1/2)10)n = 0.001
ln (0.001) = n ln(1- (1/2)10)
n = 7071
It need atleast 7071 people flipping coins to have a 99.9% chance that someone will get 10 tails.
Q.9
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Q.10
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Q.12
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Q.13
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Q.14
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Q.15
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Q.16
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Q.17
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Q.18
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Q.19
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Q.20
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Q.21
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Q.22
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Q.23
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Q.24
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Q.25
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Q.26
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Q.27
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Q.28
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Q.29
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Q.30
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Q.31
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Q.32
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Q.33
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Q.34
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Q.35
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Q.36
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Q.37
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Q.38
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Q.39
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Q.40
