Complex Number - Algebra -Multiple Correct Type Questions(JEE ADVANCED)

 Q.1

Correct Answer is:A,D
Solution Explain:












Q.2

Correct Answer is:A,B,C,D
Solution Explain:










Q.3

Correct Answer is:A,B,D
Solution Explain:









Q.4

Correct Answer is:A,D
Solution Explain:








Q.5

Correct Answer is:A,C,D
Solution Explain:










Q.6

Correct Answer is:A,B
Solution Explain:









Q.7

Correct Answer is:A,B,C,D
Solution Explain:








Q.8

Correct Answer is:A,B,D
Solution Explain:








Q.9

Correct Answer is:B,C
Solution Explain:

x4 - 3x2 - 4 = 0 and 2x - 3y + 5 = 0
⇒ (x2 - 4)(x2 +1) = 0 and 2x - 3y +5 = 0
⇒ (x,y) = (2,3) or
 









Q.10

Correct Answer is:A,B,C,D
Solution Explain:










Q.11

Correct Answer is:A,B,C,D
Solution Explain:











Q.12

Correct Answer is:A,C,D
Solution Explain:










Q.13

Correct Answer is:A,C
Solution Explain:










Q.14

Correct Answer is:A,D
Solution Explain:










Q.15

Correct Answer is:B,C
Solution Explain:










Q.16

Correct Answer is:A,D
Solution Explain:









Q.17

Correct Answer is:C,D
Solution Explain:










Q.18

Correct Answer is:A,C,D
Solution Explain:










Q.19

Correct Answer is:A,D
Solution Explain:









Q.20

Correct Answer is:A,B,C,D
Solution Explain:








Q.21

Correct Answer is:B,C,D
Solution Explain:











Q.22

Correct Answer is:B,D
Solution Explain:











Q.23

Correct Answer is:B,C
Solution Explain:









Q.24

Correct Answer is:A,B,D
Solution Explain:












Q.25

Correct Answer is:A,B,C,D
Solution Explain:









Q.26

Correct Answer is:A,C,D
Solution Explain:











Q.27

Correct Answer is:C,D
Solution Explain:










Q.28

Correct Answer is:C,D
Solution Explain:

We have x2 + x + 1 = (x – ω)(x – ω2)
Since f(x) is divisible by x2 + x + 1, f(ω2) = 0, f(ω2) = 0, so
P(ω3) + ωQ(ω3) = 0 ⇒ P(1) + ωQ(1) = 0            …… (1)
P(ω6) + ω2Q(ω6) = 0 ⇒ P(1) + ω2Q(1) = 0          ……. (2)
Solving (1) and (2), we obtain
P(1) = 0 and Q(1) = 0
Therefore, both P(x) and Q(x) are divisible by x – 1. Hence, P(x3) and Q(x3) are divisible by x3 –1 and so by x – 1
Since f(x) = P(x3) + xQ(x3), we get f(x) is divisible by x – 1.






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